लेखक
Vinjeet Vedic Arithmetic Book || 1 || Chapter 08.05 || Subtracting by Base (Part 5A)
Author
ॐ जितेन्द्र सिंह तोमर
(M.A., B. Ed., MASSCOM, DNYS )
(Specialist in Basic and Vedic Maths)
Subtraction from Base 10 or 100 or 1000
निखिलं नवतश्चरमं दशत:
Nikhilaṃ navataścaramaṃ daśataḥ -
All from 9, and the last from 10.
Sutra: Nikhilam Navatashcharama Dashat: This is a popular formula of Vedic maths, according to this formula (all from 9, and last from 10) is used to subtract a number from 10ⁿ and multiply two numbers close to 10ⁿ.
Practitioners of Vedic mathematics find it very effective for numbers close to 10ⁿ, even more effective than the famous sutra: Urdhva Tiryagbhyan.
आधार 10 या 100 या 1000 से घटाव
निखिलं नवतश्चरमं दशत:
निखिलं नवतश्चरमं दशतः - सभी 9 से, और अंतिम 10 से।
सूत्र: निखिलं नवतश्चरमं दशत: यह एक लोकप्रिय सूत्र है, इस सूत्र के अनुसार (सभी 9 से, और अंतिम 10 से) का उपयोग किसी संख्या को 10n से घटाने और 10n के करीब दो संख्याओं को गुणा करने के लिए किया जाता है।
यह वैदिक गणित के अभ्यासी इसे 10n के करीब की संख्या के लिए बहुत प्रभावी पाते हैं, यहां तक कि प्रसिद्ध सूत्र: ऊर्ध्व तिर्यगभ्यां से भी अधिक प्रभावी।
Subtraction of number from 10n:
As an illustration, let us use this Sūtra for:
As an illustration, let us use this Sūtra for:
1.Subtraction - Base method 5A |
Subtraction using appropriate base
1. One digit number (base 10)
10 – 1 = 9
10 – 2 = 8
10 – 3 = 7
10 – 4 = 6
10 – 5 = 5
10 – 6 = 4
10 – 7 = 3
10 – 8 = 2
10 – 9 = 1
2. Two digit numbers (base 100)
Ex. (1) 100 – 73
Take 73
The last digit 3 is subtracted from 10 is 10 – 3 = 7
And, the other digits 7 is subtracted from 9 is:
9 – 7 = 2
Hence, 27
The last digit 3 is subtracted from 10 is 10 – 3 = 7
And, the other digits 7 is subtracted from 9 is:
9 – 7 = 2
Hence, 27
Or
73
= (9–7)/(10–3)
= 2/7
= 27
Ex. (02) 100 – 23
Sol.
23
= (9–2)/(10–3)
= 7/7
= 77
Thus, 100 – 23 = 77
For Practice
Practice Time (1)
(1) 100 – 19
(2) 100 – 38
(3) 100 – 57
(4) 100 – 75
(5) 100 – 83
(6) 100 – 32
(7) 100 – 25
(8) 100 – 14
(9) 100 – 13
(10) 100 – 24
(11) 100 – 85
(12) 100 – 66
(13) 100 – 47
(14) 100 – 61
(15) 100 – 69
(16) 100 – 43
(17) 100 – 44
(18) 100 – 63
(19) 100 – 36
(20) 100 – 57
3. Three digit numbers (base 100)
Ex. (03) 1000 – 249
Sol.
249
= (9–2)/(9–4)/(10–9)
= 7/5/1
= 751
Thus, 1000 – 249 = 751
Ex. (04) 1000 – 543
Sol.
249
= (9–5)/(9–4)/(10–3)
= 4/5/7
= 457
Thus, 1000 – 543 = 457
Practice Time (2)
(1) 1000 – 147
(2) 1000 – 322
(3) 1000 – 526
(4) 1000 – 626
(5) 1000 – 113
(6) 1000 – 232
(7) 1000 – 548
(8) 1000 – 746
(9) 1000 – 924
(10) 1000 – 239
(11) 1000 – 431
(12) 1000 – 654
(13) 1000 – 856
(14) 1000 – 137
(15) 1000 – 333
हल:– (1) क्षैतिज विधि
1000 – 147
Ex. (03) 1000 – 249
Sol.
249
= (9–2)/(9–4)/(10–9)
= 7/5/1
= 751
Thus, 1000 – 249 = 751
Ex. (04) 1000 – 543
Sol.
249
= (9–5)/(9–4)/(10–3)
= 4/5/7
= 457
Thus, 1000 – 543 = 457
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